Question

The peak value of AC through a register of 100Ω is 2A. If the frequency of AC is 50 Hz. Find the heat produced in the resistor in one cycle​

Answer 1

Detailed solution is given in attachment

Answer 2

4 calorie heat will be produced up.

Given: register of 100Ω is 2A

To find: Heat produce
Solution:

Thermodynamics, skill of the friendship betwixt heat, work, hotness, and strength. In broad conditions, thermodynamics handles the transfer of strength from individual place to another and from individual form to another. The key idea is that heat is a form of strength equivalent to a positive amount of machinelike work.Heat was not in an official manner acknowledged as a form of strength as far as about 1798, when Count Rumford (Sir Benjamin Thompson), a British military engineer, seen that never-ending amounts of heat maybe create in the uninteresting of mortar barrels what the amount of heat create is equivalent to whole exhausted curving a blunt uninteresting finish.

Lets simplify it,

Peak value of current = 2 amps

R M S value of current = 2/√2 amps

Resistance value = 100

Heat generated H = I^2R

Quantity of heat generated Q = I^2Rt where t is time in sec

Frequency of current f = 50 hz

Time t for one cycle = 1/50 sec

Q = (2/√2)^2*100*1/50 = 200/50 = 4 cal

So 4 calorie will be burn up.

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