Question

The percentage change in the fringe width in young's double slit experiment when the distance of the screen from the slits is increased by 25% and the separation between the slits is halved is *



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Answer 1

Answer:

Correct option is

A

width of slits

β=λ

d

D

So by increasing d, that is width of slits, we can decrease fringe width.

Answer. A) width of slits.

Answer 2

The answer is 150%.

Given:

The distance of the screen from the slits is increased by 25%

The separation between the slits is halved.

To Find:

The percentage change in the fringe width

Solution:

Let the distance of the screen from the slits be D.

Let the distance between the slits be d.

The fringe width is proportional to $\frac{D}{d}$.

Hence the new fringe width is $\frac{1.25D}{0.5d} = \frac{2.5D}{d}$

Therefore the percentage change is 150%.

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