The percentage change in the volume of the given mass of a gas at constant temperature is 50%(increases) .calculate the percentage change in the pressure of the gas.
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Hello friend,
◆ Answer-
∆P/P = -33 %
◆ Explaination-
# Given-
∆V/V = 50%
# Solution-
Let V & V' be initial & final volume of the gas.
Let P & P' be its pressure at respective times.
We have-
∆V = V' - V = 50% V
V' = 1.5 V
According to ideal gas eqn -
PV = P'V'
P' = PV / V'
P' = PV / 1.5V
P' = 0.67P
Change in pressure is -
∆P = P' - P
∆P = 0.67P - P
∆P = -0.33 P
∆P/P = -33 %
Therefore, pressure of the gas will decrease by 33%.
Hope this helps you...
◆ Answer-
∆P/P = -33 %
◆ Explaination-
# Given-
∆V/V = 50%
# Solution-
Let V & V' be initial & final volume of the gas.
Let P & P' be its pressure at respective times.
We have-
∆V = V' - V = 50% V
V' = 1.5 V
According to ideal gas eqn -
PV = P'V'
P' = PV / V'
P' = PV / 1.5V
P' = 0.67P
Change in pressure is -
∆P = P' - P
∆P = 0.67P - P
∆P = -0.33 P
∆P/P = -33 %
Therefore, pressure of the gas will decrease by 33%.
Hope this helps you...
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