Question

The percentage composition by mass of a solution is 20% urea(NH2CONH2 ), 40% glucose (C6H12O6 ) and 40% water( H2O).Calculate the mole fraction of each component of the solution?

Answer 1

Given that,

The percentage composition by mass of a solution is

Percentage of urea =20%

Percentage of glucose =40%

Percentage of water =40%

We need to calculate the moles of urea

Using formula of moles

$M=\dfrac{20}{60.06}$

$M=0.33\moles$

We need to calculate the moles of glucose

Using formula of moles

$M=\dfrac{40}{180.2}$

$M=0.22\moles$

We need to calculate the moles of water

Using formula of moles

$M=\dfrac{40}{18.0}$

$M=2.22\moles$

We need to calculate the mole fraction of each component of the solution

Using formula for mole fraction

For urea,

$x_{urea}=\dfrac{\text{moles of urea}}{\text{moles of urea+moles of glucose+moles of water}}$

Put the value into the formula

$x_{urea}=\dfrac{0.33}{0.33+0.22+2.22}$

$x_{urea}=0.119$

For glucose,

Put the value into the formula

$y_{glucose}=\dfrac{0.22}{0.33+0.22+2.22}$

$y_{glucose}=0.079$

For water,

Put the value into the formula

$z_{water}=\dfrac{2.22}{0.33+0.22+2.22}$

$z_{water}=0.801$

Hence, The mole fraction of each component of the solution is 0.119, 0.079 and 0.801

Answer 2

Hope this will help you