Question

the percentage composition of a compound on analysis to be fe=69.9%and o=30.1%. find the emperical formula​

Answer 1

Answer:

Fe2O3

Explanation:

Fe                                 O

69.9/56=1.2482mol   30.1/16=1.8812mol

simplest mole ratio:-

fe:-1.2482/1.2482=1       o;-1.8812/1.2482=1.50

so multiplyit by 2

Fe:-1*2=2                        o:-  1.5*2=3

so Fe2O3