Question

The percentage composition of a gas is nitrogen 82.35% , Hydrogen 17.64% . Find the empirical formula of the gas.
See the attachment it contains the solution of the question but the thing is I can't understand the Sol
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Answer 1

answer is attached below same thing but if you understand then its fine or I will find out for you something

dekho

Total composition =82.35 + 17.64=100

therefore Nitrogen present in 100g molecule is

82.35g × 1mol N/14 g N = 5.88 mol N

and amount of H is 17.64 × 1mol H/1 g H

= 17.64 mol H

Relative ratio of N and H is therefore N:H

toh waise 1:3

Answer 2

ᴘʜᴏᴛᴏꜱʏɴᴛʜᴇꜱɪꜱ ɪꜱ ᴀ ᴘʀᴏᴄᴇꜱꜱ ᴜꜱᴇᴅ ʙʏ ᴘʟᴀɴᴛꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ᴏʀɢᴀɴɪꜱᴍꜱ ᴛᴏ ᴄᴏɴᴠᴇʀᴛ ʟɪɢʜᴛ ᴇɴᴇʀɢʏ ɪɴᴛᴏ ᴄʜᴇᴍɪᴄᴀʟ ᴇɴᴇʀɢʏ ᴛʜᴀᴛ, ᴛʜʀᴏᴜɢʜ ᴄᴇʟʟᴜʟᴀʀ ʀᴇꜱᴘɪʀᴀᴛɪᴏɴ, ᴄᴀɴ ʟᴀᴛᴇʀ ʙᴇ ʀᴇʟᴇᴀꜱᴇᴅ ᴛᴏ ꜰᴜᴇʟ ᴛʜᴇ ᴏʀɢᴀɴɪꜱᴍ'ꜱ ᴍᴇᴛᴀʙᴏʟɪᴄ ᴀᴄᴛɪᴠɪᴛɪᴇꜱ.