Chemistry, asked by sabyasachipanda5571, 9 months ago

The percentage composition of Cute in CuSO4(Cu=63.5g,S=32g,O=16g)

Answers

Answered by Krity10

2

Explanation:

Percentage composition: mass of element ×100 / total mass of solution

total mass = 63.5+32+16×4 = 159.5

so

CU = 63.5 ×100/159.5

=39.811

Answered by gavaskarketan

0

50.54

Explanation:

63.5+32+16=111.5×4÷100

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