Question

the percentage composition of gas - nitrogen 82.35%
hydrogen 17.64%
Q1 Find the empirical formula of gas ( given relative atomic mass of N=14,H=1)​

Answer 1

(☞ﾟ∀ﾟ)☞answer

Total composition = 82.35+17.64=100

Therefore Nitrogen present in 100 g molecule is:

82.35g N×

14g N

1 mol N

=5.88 mol N

and amount of H is: 17.64 g H×

1 g H

1 mol H

=17.64 mol H

Relative ratio of N and H is therefore: N:H::5.88:17.64=1:3

N

1

H

3

Emperical formula is NH

3

Hope it helps ❤️❤️

shivanya ❤️❤️