Question

The percentage composition of N in the urea molecule CO(NH2)2 is: *

45.65
46.66
47.90
12.8​

Answer 1

Explanation:

Correct option is

A

46.6% N

Molecular weight of H

2

NCONH

2

=4+28+12+16=60g

60g of urea contains 28g of N

∴ % of N=

60

28

×100=46.6%

Answer 2

Answer:

46.66%

Explanation:

ATOMIC MASS OF

C=12

O=16

N=14

H=1

THEREFORE

TOTAL MOLECULAR MASS =

12+16+14×2+1×2×2=60 amu

N = 14×2= 28

NOW % OF N = 28/60×100=46.66

THEREFORE THE RIGHT ANSWER IS

46.66%