the percentage error in measurement of surface area of sphere is 2% , then find the percentage error in measurement of radius
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0
Explanation:
Given, Error in a radius of the sphere is 2%
it meansΔr=2%
Now, the surface area of the sphere is
A=4πr^2
A/ΔA = 2Δr / r
A / ΔA = 2×2 / 1000
= 0.04
ΔA / A×100 = 0.04 × 100 = 4%
it means % error in surface area of its measurements is 4%
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Answered by
1
Explanation:
Given, Error in a radius of the sphere is 2%
it meansΔr=2%
Now, the surface area of the sphere is
A=4πr
2
A
ΔA
=
r
2Δr
A
ΔA
=
1000
2×2
=0.04
A×100
ΔA
=0.04×100= 4%
it means % error in surface area of its measurements is 4%
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