Physics, asked by Chandrashekar1281, 10 months ago

The percentage error in measuring mass and velocity of a particle are respectively 2% and 1% and percentage error in measuring its kinetic energy is

Answers

Answered by akashdabas12
2

Answer:

KE= 1/2 mv^2

so it is a multiplicative error

error in mass = 2× its power=2×1=2

error in velocity=1× its power=1×2=2

add the errors 2+2= 4%

answer= 4%

Answered by azizalasha
1

Answer:

4%

Explanation:

E = mv²/2

log E = log m + 2 log v - log2

ΔE/E = Δm/m + 2Δm/m = 2 + 2 = 4%

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