Chemistry, asked by manish710479, 11 months ago


The percentage error in the mass and speed are 2% and 3% respectively. What is the
dare 2% and 3% respectively. What is the linear magnification of
maxmum error in kinetic energy calculated using these quantities?

Answers

Answered by sriram3387
1

K=1/2mv2

delta K/K =delta m/m +2*delta v/v

percentage error in Kinetic energy delta K/K*100=delta m/m*100+2 delta v/v*100=2+2*3=8

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