Physics, asked by dhapodkar4255, 9 months ago

The percentage error in the measurement of side of a cube is 1%what will be the percentage error calculation of its volume

Answers

Answered by zahaansajid
16

Answer:

Percentage error in volume = 3%

Explanation:

We know that, for a cube of side 'a' volume is given by

Volume = a³

Hence, on taking percentage error on both sides we get,

\dfrac{\Delta V}{V} = 3\dfrac{\Delta a}{a}

We are multiplying \dfrac{\Delta a }{a} by 3 because it had the power 3

Given in the question that,

Percentage error in side = \dfrac{\Delta a }{a}  = 1%

Putting this value in we get,

\dfrac{\Delta V}{V} = 3 \times 1 = 3%

Answered by Anonymous
187

Answer

Let the side of cube be a

Volume =  {a}^{3}

Percentage error = n ( percentage error in value of a )

where n is the power of a

Percentage error in volume =

 \frac{\Delta v}{v}   \times 100\% = 3 \frac{\Delta a}{a}

\frac{\Delta a}{a}  = 1% ( given)

 \frac{\Delta v}{v}   \times 100\% = 3 \times 1\% = 3\%

ADDITIONAL INFORMATION :-

Let n be number of values for a physical quantity which is a_1 , a_2 , a_3 - - - a_n

Average value =  \frac{a_1 + a_2 + a_3 - - - a_n}{n}

Absolute error = Difference between true value and measured value.

Thanks

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