The percentage error in the measurement of the voltage v is 3% and in the measurement of the current is 2%.find the percentage error in the measurement of the resistance?
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as we know percentage error=∆a/a×100
therefore ∆r/r×100=∆v/v×100+∆i/i×100
where percentage error in voltage=3%
and percentage error in current=2%
∆r/r×100=3%+2%
∆r/r×100=6%
therefore ∆r/r×100=∆v/v×100+∆i/i×100
where percentage error in voltage=3%
and percentage error in current=2%
∆r/r×100=3%+2%
∆r/r×100=6%
shivansh567:
ans is 5%
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