Physics, asked by vdaheriya230, 2 days ago

The percentage error in the measurement of the volume of a cube is 8%. Then the percentage error in the measurement of side of the cube will be.​

Answers

Answered by priyankachaudhry1994
0

Answer:

0.75 is the correct answer of the question

Answered by pradyun2007
0

Answer:

Explanation:

Given:

Percentage error in measurement of side of cube = 2 %

i.e., (Δa/a) × 100 = 2 %

To Find:

Percentage error in the volume and area of cube.

Calculation:

- Area of cube, A = a²

⇒ Percent error in area is given by

(ΔA/A) × 100 =2 (Δa/a) × 100

⇒ (ΔA/A) × 100 = 2 × 2

⇒ (ΔA/A) × 100 = 4 %

- Volume of cube, V = a³

⇒ Percent error in volume is given by

(ΔV/V) × 100 = 3 (Δa/a) × 100

⇒ (ΔV/V) × 100 = 3 × 2

⇒ (ΔV/V) × 100 = 6 %

- Thus, % error in area and volume is 4 % and 6 % respectively

Similar questions