Math, asked by jareenas83, 1 year ago

The percentage increase in the surface area of a cube when each side is doubled,is




Answers

Answered by Anonymous
19

Answer:


Step-by-step explanation:

The percentage increase in the surface area of a cube when each side is doubled is :  

A) 1.5

 B) 0.5

C) 2

 D) 3

Correct Answer:

 D) 3

Description for Correct answer:

Surface area of a cube = 6X(side)2

Let the side of cube = 'a'

then its surface area = 6a2

new side of a cube = 2a

then its surface area = 6(2a)2=24a2

Therefore, Percentage increase = 24a2−6a26a2×100

= 18a26a2×100=300%

Answered by gaurav2013c
0
Let the Side of cube be a

Original Surface area= 6a^2 -----(1)

New side = 2a

New surface area= 6 (2a)^2

= 6 ( 4 a^2)

= 24 a^2 ----(2)

From equation 1 and 2 , we can say that

New area is four time of original area ..

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