The percentage increase in the surface area of a cube when each side is doubled,is
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Answer:
Step-by-step explanation:
The percentage increase in the surface area of a cube when each side is doubled is :
A) 1.5
B) 0.5
C) 2
D) 3
Correct Answer:
D) 3
Description for Correct answer:
Surface area of a cube = 6X(side)2
Let the side of cube = 'a'
then its surface area = 6a2
new side of a cube = 2a
then its surface area = 6(2a)2=24a2
Therefore, Percentage increase = 24a2−6a26a2×100
= 18a26a2×100=300%
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Let the Side of cube be a
Original Surface area= 6a^2 -----(1)
New side = 2a
New surface area= 6 (2a)^2
= 6 ( 4 a^2)
= 24 a^2 ----(2)
From equation 1 and 2 , we can say that
New area is four time of original area ..
Original Surface area= 6a^2 -----(1)
New side = 2a
New surface area= 6 (2a)^2
= 6 ( 4 a^2)
= 24 a^2 ----(2)
From equation 1 and 2 , we can say that
New area is four time of original area ..
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