Question

The percentage increase in the surface area of cube, when each side is increased to 3/2 times the original length is​

Answer 1

Step-by-step explanation:

Given  

The percentage increase in the surface area of cube, when each side is increased to 3/2 times the original length is

We know that surface area of a cube = 6 x (side)^2

So surface area of the cube = 6 a^2

Now each side is increased to 3/2 times the original length

So surface area will be 6 (3/2 a)^2

                                = 6 x 9/4 a^2

                                = 27 / 2 a^2

Now we need to find the percentage increase.

So percentage increase will be 27/2 a^2 – 6 a^2 / 6 a^2 x 100

                                           = 15/2 a^2 / 6 a^2 x 100

                                           = 5/4 x 100

                                           = 125%

Answer 2

Answer:

125 %

5/4×100 = 125