Question

The percentage loss in weight after heating a pure sampke of potassium chlorate will be

Answer 1

2KClO3 = 2KCl + 3O2
2 × 122.5 shows a weight loss of 3 × 32gO2
100 g shows a weight loss = 3×32×100/2×122.5
= 39.17
Therefore, a pure sample of potassium chlorate will be 39.17.

Answer 2

Hey dear,

● Answer -
Loss of weight = 39.18 %

● Explaination -
- Decomposition of potassium chlorate by heating occurs as
KClO3 ---> KCl + 1.5 O2

In terms of weight,
122.5 g KClO3 => 1.5×32 g O2
122.5g KClO3 => 48 g O2

100 g of KClO3 loses -
x = 100 × 48 / 122.5
x = 39.18 g

Therefore, percentage loss of weight in KClO3 on thermal decomposition is 39.18 %.

Hope this helps...