The percentage of an iceberg (freshwater of density 0.92 g/cm3 ) below the waterline in an ocean (saltwater of density 1.025 g/cm3 ) will be approximately a) 20% b) 80 % c) 90 % d) 10 %
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Given : Density of ice = 0.92 g cm Density of sea water = 1.025 g cm -3 Volumn of the ice berg above water = 800cm Let'v' be the volume of iceberg immereder in water
V As per the law of floatation,
V Density of ice Density of sea water
0.92
= 0.8976 V 1.025
V
=
v= 0.8976V
Volume of the iceberg over the surface of sea water is given by: V (1 – 0.8976) = 800 → V = 800/(1 – 0.8976) → V = 7812.5 cm
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