The percentage of available chlorine in a sample of bleaching powder, CaOCl·2H2O is
Answers
Answered by
0
CaOCl
2
. 2H
2
O →Cl
2
1 mole of CaOCl
2
. 2H
2
O gives 1 mole Cl
2
163 g of sample gives 71g of available Chlorine
Therefore, % available chlorine =
163
71
× 100= 43.5%
Answered by
1
Answer:
55% of chlorine
hope it will help you
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