Question

.
The percentage of Carbon, Hydrogeon and Oxygen in an orgonic substance are 40, 6.666 and 53.34 respectively. Molecular mass of the compound is 180 g mol-1. Find the value of integral
number.​

Answer 1

Answer:

Empirical formula CH₂O

N = 6

Explanation:

Carbon -- 40% -- 12 -- 40/12 = 3.33

Hydrogen -- 6.66% -- 1 -- 6.66/1 = 6.66

Oxygen -- 53.34% -- 16 -- 53.34/16 = 3.33

The least atomic ratio from these is 3.33

So, to get the simplest ratio, divide each by 3.33

We get C:H:O = 1:2:1

So, the empirical formula is CH₂O

Empirical formula Weight (EFW) = 12 + 2 + 16 = 30

Now, given that, molecular mass is 180 (MM = 180).

Let the molecular formula be (CH₂O)n where n is a positive integer.

n is given my MM / EFW

So, n = 180/30 = 6