the percentage of carbon is ca(Hco3
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Answered by
0
Answer:
CaCO
3
1Ca atom molar mass= 40
1C atom molar mass = 12
1Oxygen atom molar mass = 16
Total = 40+12+16×3
=100
%Ca=
100
40
×100
=40%
Answered by
2
Ca = 40 ,H= 1 ,C= 12, O= 16
weight of compound = 40 *1 + 1*1+ 1*12 + 16*3
= 40+1+12+48
= 101 amu
percentage = mass of element/total mass of compound * 100
= 12/101 *100
= 12.12 %
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