The percentage of cu2o in cuso4 5h2o
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Answered by
4
Molar mass of CuSO4 = 63.5+32+16X4 = 159.5
Molar mass of CuSO4.5H2O = 159.5 + 5(2 + 16)
= 159.5 + 5x18
= 159.5 + 90
= 249.5
Percentage of CuSO4 = 159.5/249.5 x 100
= 63.93%
Molar mass of CuSO4.5H2O = 159.5 + 5(2 + 16)
= 159.5 + 5x18
= 159.5 + 90
= 249.5
Percentage of CuSO4 = 159.5/249.5 x 100
= 63.93%
Answered by
5
Atomic mass of the Copper = 63.5 g.
Atomic mass of the Sulphur = 32 g.
Atomic mass of the Oxygen = 16 g.
Atomic mass of the Hydrogen 1 g.
∴ Molar mass of CuSO₄ = 63.5 + 32 + 16 × 4
= 159.5 g.
Also, The molar mass of CuSO₄5H₂O = 159.5 + 5(2 + 16)
= 159.5 + 5x18
= 159.5 + 90
= 249.5 g.
Using the Formula,
% of the Substance = Mass of the Substance/Total mass × 100%
∴ % of Substance = 159.5/259.5 × 100%
= 63.92 %
Hope it helps.
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