The percentage of error in the measurement of mass and its velocity is 1percent and 0.5percent find the percentage of error in its kinetic energy
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Answer:
2%
Explanation:
KE = 1/2 (M) (V^2)
so, percent change in kinetic energy is (%change in mass) + 2(%chance in velocity)
therefore %∆K.E = (1) + 2(0.5)
= 1+ 1
=2
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