Question

the percentage of ethyl alcohol by weight is 46% in a mixture of ethanol and water.The mole fraction of alcohol in this solution

Answer 1

Mole fraction is a way of expressing concentration of a mixture or a solution. It makes use of the mole values of the components making up the mixture. 

The mole fraction of a component of a mixture is calculated by dividing the mole of that component by the total moles of the solution. Here is how it is done: 

                mole fraction = mole of one of the component of the solution
                                                  total moles of the solution

Calculating the mole fraction of ethanol for the question above: 

Note: we will use a 100 g sample of this solution for the calculation.

Percentage by weight of ethyl alcohol is 46%...that means in 100 g of this solution is 46 g while the mass of the water will be 54% of 100 g = 54g.

Find the moles of water and the ethyl alcohol {molar mass of water(H₂O) = 18 and molar mass of ethyl alcohol(C₂H₆O = 46}

Moles = mass/molar mass

moles of ethanol = 46/46 = 1

moles of water = 54/18 = 3

total moles = 1 + 3 = 4

Mole fraction of ethanol is: 

                     Mole of ethanol            =   1/4
                   Total mole of solution


Therefore the mole fraction is 1/4 or 0.25

Answer 2

Answer:

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