Question

The percentage of ionic character of HX having bond length = 1.62 Aº and observed dipole moment = 0.39 D is​

Answer 1

Calculated μ=4.8×10−10 esu ×1.62×10−8cm=7.776 D

Percentage ionic character = 0.397.776×100=5%

Percentage covalent character = 100−5=95 %

Answer 2

Answer:

5%

Explanation:

Ionic character=  

Theoretical dipole moment

Observed dipole moment

​

×100

Theoretical dipole moment=(1.6×10  

−19

C)×(1.61×10  

−10

m)=2.576×10  

−29

Cm

1D=3.33564×10  

−30

Cm

Percentage ionic character=  

2.576×10  

−29

 

0.38×3.33564×10  

−30

 

​

×100=5%