Question

The percentage of nitric acid (HNO3) [ H=1, N=14, O=16]

Answer 1

MASS OF H=1

MASS OF N=14

MASS OF 0³=16×3=48

MASS OF HNO³=48+14+1=63

%MASS OF H=1/63×100=100/63≈1.58%

%MASS OF N=14/63×100=200/9≈22.22%

%MASS OF O=48/63×100≈76.19%