The percentage of nitrogen in urea is about?
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the molecular formula of Urea in CH4N2O,
thus the molecular weight= 12+ 4(1)+ 2(14)+ 16=60
Weight of nitrogen in urea=2(14)=28
Percentage of nitrogen=100*weight on nitrogen present/ molecular weight
=100*28/60=46.67%
hope this helps!!
thus the molecular weight= 12+ 4(1)+ 2(14)+ 16=60
Weight of nitrogen in urea=2(14)=28
Percentage of nitrogen=100*weight on nitrogen present/ molecular weight
=100*28/60=46.67%
hope this helps!!
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0
Answer:
46
Explanation:
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