The percentage of occurance in a sample of 10y5 and 11y5 are 20% and 80% respectively. Find the atomic mass of the element
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Let the percentage abundance of first isotope be
5
10
B=x
Hence the percentage abundance of second isotope is
5
11
B=100−x.
Avg atomic mass =
100
x×10+(100−x)×11
1080=10x+1100−11x
or, x=20.
Hence the %abundance of the two isotopes are 20 & 80 %.
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