Question

The percentage of oxygen in sulphur (iv) oxide is? [S=32, O=16]

Answer 1

Answer:50%

Explanation:% of oxygen=(weight of oxygen in so2÷total weight of so2)×100

=(32÷64)×100

=(1÷2)×100

=50%

Answer 2

The percentage of oxygen in sulphur oxide is 50%.

Step-by-step explanation:

Given: molecular mass of sulphur is 32 g/mol, and oxygen is 16 g/mol.

To find: the percentage of oxygen in sulphur (IV) oxide.

Formula to be used: mass percentage $=\frac{mass -of-sulphur}{total-mass} *100$

Step 1 of 1

Mass of oxygen = 32 g/mol

Mass of sulphur oxide = 32+2(16) = 64 g/mol

So, the mass percentage =

$Percentage = \frac{32}{64} *100\\\\=50.0$

The percentage of oxygen in sulphur oxide is 50%.