The percentage of p character in hybrid orbital of the central atom of water molecule
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Answered by
12
Answer:
ans of this que is 75%
Explanation:
water=H2o
no. of hybrid orbitals= 1/2 × [no. of valency electrons of central atom] + [no.of monovalent atom]
H2o = 1/2×(6+2)
= 4
= sp3
so, s=25%
and p=75%
Answered by
1
Explanation:
75 percentage is the answer
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