Question

The percentage of p-character in the orbitals forming p - p bonds in p4 is

Answer 1

The percentage of p-character in forming P-P bonds in P4 molecule is: 0. In forming P4molecule, P atom uses sp3 hybrid orbitals. Thus, p-character in hybrid orbitals is 75%.

Answer 2

Answer: Percentage of p-character in the orbitals of $P_4$ molecule if 75%.

Explanation: To calculate the hybridization, we should know the number of bond pairs and lone pairs per element.

From the structure (attached), it is visible that

Number of bond pairs per P-atom = 3

Number of lone pairs per P-atom = 1

Number of orbitals = Number of bond pairs + number of lone pairs

Number of orbitals = 3 + 1 = 4

If the number of orbitals is 4, then the hybridization will be $sp^3$

% character of p in $sp^3$ is 75%.