The percentage of P₂O₅ in diammonium hydrogen phosphate (NH₄)₂HPO₄ is
(a) 23.48
(b) 46.96
(c) 53.78
(d) 71.00
Answers
Answered by
4
2 (NH₄)₂HPO₄ ⇒ P₂O₅
2 moles of diammonium hydrogen phosphate, yield 1 mole of P₂O₅
The molar mass of (NH₄)₂HPO₄ is given by =
= 36 + 1 + 31 + 44
= 132g
Molar mass of P₂O₅ is given by =
= 62 + 80
= 142g
So, percentage of P₂O₅ is
= [142 / (2) x 132] x100
= 142 / 264 x 100
= 53.78%
Therefore percentage of P₂O₅ is 53.78%.
hope it will helpfulfor you
2 moles of diammonium hydrogen phosphate, yield 1 mole of P₂O₅
The molar mass of (NH₄)₂HPO₄ is given by =
= 36 + 1 + 31 + 44
= 132g
Molar mass of P₂O₅ is given by =
= 62 + 80
= 142g
So, percentage of P₂O₅ is
= [142 / (2) x 132] x100
= 142 / 264 x 100
= 53.78%
Therefore percentage of P₂O₅ is 53.78%.
hope it will helpfulfor you
Answered by
0
Answer:
(c) 53.78
Explanation:
hope it is helping..
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