Question

The percentage of sulphur in an organic compound whose 0.32gm produces 0.23gm of BaSo4

Answer 1

Answer:

Answer

Correct option is

C

10

Molar mass of BaSO  

4

​

=233g

Let the mass of BaSO  

4

​

 formed=0.233g

we know that,

32g of Sulphur is present in 1 mol. of BaSO  

4

​

 

∴ 233g BaSO  

4

​

 contains 32g sulphur.  

⇒0.233g of BaSO  

4

​

 contains  

233

32×0.233g

​

 of sulphur

% of sulphur=  

233×0.32

32×0.233×100

​

 

=  

74.56

745.6

​

 

=10%

Hence, correct option is c