Question

The percentage of the elements calcium carbonate and oxygen in sample of calcium carbonate compound was given as 40% calcium, 12% carbon,48 % oxygen..
If the law of constant proportions is true.
What mass of these elements will be present in 1.5g of another sample of calcium carbonate.??

Answer 1

Answer: Calcium will be 0.6 g , carbon will be 0.18 g and oxygen will 0.72 g in the given 1.5 g of calcium carbonate sample.

Explanation:

According to question percentage of element in a sample is

Ca=40%, C=12% and O=48%

So, in a given sample of 1.5 g

$\%Ca=1.5\times \frac{40}{100}=0.6 g$

$\%C=1.5\times \frac{12}{100}=0.18 g$

$\%O=1.5\times \frac{48}{100}=0.72 g$

Answer 2

Answer:

mass of calcium in 1.5 g sample of caco3

1.5*40/100= 0.6

1.5*12/100= 0.18

1.5*48/100= p. 72

Explanation:

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