The percentage proportion of C H and N in an organic compound are 62.07 10.34 and 14.0 respectively. find its Empirical formula
Answers
Answer:
100 g of compound will contain 62.07 g of C, 10.34 g of H, 14.0 g of N and 13.59 g of O.
The atomic masses of C, H, N and O are 12 g/mol, 1 g/mol, 14 g/mol and 16 g/mol respectively.
The number of moles of C =
12 g/mol
62.07 g
=5.17 mol.
The number of moles of H =
1 g/mol
10.34 g
=10.34 mol.
The number of moles of N =
14 g/mol
14 g
=1 mol.
The number of moles of O =
16 g/mol
13.59 g
=0.85 mol.
The mole ratio C:H:N:O=5.17:10.34:1:0.85≃5:10:1:1
Hence, the empirical formula is C
5
H
10
NO
The empirical formula mass =5(12)+10(1)+14+16=100 g/mol
The ratio of molecular formula mass to empirical formula mass =
100
144
=1.44
Hence, the molecular formula of organic compound is (C
5
H
10
NO)
1.44
.
Answered By
Refer the attachment for your answer
