Question

The percentage volumes of milk in three solutions A, B and C form a geometric
progression in the order. If we mix the first, second and third solutions in the ratio 2:3:4
by volume, we obtain a solution containing 32% milk. If we mix them in the ratio 3:2:1 by
volume, we obtain a solution containing 22% milk, what is the percentage of milk in A?​

Answer 1

Step-by-step explanation:

Suppose volumes of milk percentage in A,B,C are a, ar, ar^2 respectively.

2a + 3ar + 4ar^2 = 32 x 9.

3a + 2ar + ar^2 = 22 X 6.

a= 12, r = 2.

The percentage of milk in A = 12%.

Answer 2

Answer:

It is 21

Step-by-step explanation:

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