the peremeter of parallelogram is 140cm if one side is longer than other by 10cm find the length of each
Answers
Answered by
1
let one side be x cm
other side = x + 10 cm
since opposite sides of a parellalogram are equal,
3rd Side = x
4th = x + 10
perimeter of parellalogram
= side + side + side + side
140 = x + x + 10 + x + x + 10
140 = 4x + 20
140 - 20 = 4x
120 = 4x
x = 120/4
x = 30
1st side = x = 30cm
2nd angle = x + 10 = 40cm
3rd side = 30cm
4th side = 40cm
other side = x + 10 cm
since opposite sides of a parellalogram are equal,
3rd Side = x
4th = x + 10
perimeter of parellalogram
= side + side + side + side
140 = x + x + 10 + x + x + 10
140 = 4x + 20
140 - 20 = 4x
120 = 4x
x = 120/4
x = 30
1st side = x = 30cm
2nd angle = x + 10 = 40cm
3rd side = 30cm
4th side = 40cm
Answered by
0
as we know perimeter of parallelogram
let the unkown side be x 2(sum of two adjacent side) so
2((10+x)+x)=140
20+4x=140
4x=140-20
x=120/4
x=30 cm
so frist side is of 30cm and another is of length 10+x=10+30=40cm
let the unkown side be x 2(sum of two adjacent side) so
2((10+x)+x)=140
20+4x=140
4x=140-20
x=120/4
x=30 cm
so frist side is of 30cm and another is of length 10+x=10+30=40cm
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