The performance bonus of 2 Associates are in the ratio 9:10. If each them receives an increase of 88 USD, the ratio of their wages will be 10:11.
What are their respective wages before the increase?
Answers
The respective wages of the associates before increase were 792 USD and 880 USD.
• Given that the ratio of the performance bonus of two associates = 9 : 10
=> Performance bonus of one associate = 9x
Performance bonus of another associate = 10x
• If they both receive 88 USD more, their wages become (9x + 88 USD) and (10x + 88 USD) respectively.
• According to the question,
(9x + 88 USD) : (10x + 88 USD) = 10 : 11
=> (9x + 88 USD) / (10x + 88 USD) = 10 / 11
On cross-multiplying,
11 (9x + 88 USD) = 10 (10x + 88 USD)
=> 99x + 968 USD = 100x + 880 USD
=> 100x - 99x = (968 - 880) USD
=> x = 88 USD
• Putting x = 88 USD, we get,
9x = 9 × 88 USD = 792 USD
10x = 10 × 88 USD = 880 USD
• Therefore, their original wages before increase were 792 USD and 880 USD respectively.