Question

The perimeter and area of a rectangular table are 80m & 384m2 respectively. Find the length and breadth of the table

Answer 1

length = 24 m, breadth = 16 m

Step-by-step explanation:

Let the length of the table be l and breadth be b

ATQ,

$2(l + b) = 80 \\l + b = \frac{80}{2} = 40$

also,

$l \times b = 384$

$l \times (40 - l) = 384$

$40l - {l}^{2} = 384$

${l}^{2} - 40l + 384 = 0$

${l}^{2} - 16l - 24l + 384 = 0$

$l(l - 16) - 24(l - 16) = 0$

$(l - 16)(l - 24) = 384$

so, l = 16, 24

as, l sould be greater, therefore we may consider l to be 24

therefore, b = 40-24=16

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