the perimeter and area of the
quadrilateral ABCD in which AB = 17 cm,
AD = 9 cm, CD = 12 cm, ZACB = 90° and
AC = 15 cm.
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Answer:
perimeter = 46 cm
Step-by-step explanation:
In triangle ACB,
by Pythagorus therum ,
BC²=17²-15²
BC²= 289-225
BC=√64
BC=8cm
Now, perimeter = AB+BC+CD+DA
= 17+8+12+9
= 46 cm
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