the perimeter and length of a rectangle is 44cms and 15 cms respectively then find its area
Answers
Answered by
2
perimeter of rectangle = 2(l+b)
44 = 2(15+b)
44/2 = 15 + b
22-15 = b
breadth = 7cm
area of rectangle = l × b
= 15 × 7 = 105 sq.cm
venkat5543:
the ratio b/w length and breadth of a rectangle is 4:3 nd its area is 300 sqmts,then find its perimeter
i will solve it later..now going for study
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l/b = 4/3 let length be 4x and breadth be 3x area of rectangle = l×b = 4x × 3x = 12x^2 but the area is given 300. 300=12x^2 300/12 = x^2 25 = x^2 so x = 5
length = 4x = 4×5=20 breadth = 3x = 3×5 =15
now u can use the formula of perimeter of rectangle = 2(l+b) to find answer
gud nyt have a nice sleep
Answered by
1
Perimeter of rectangle=2(l+b)
=2(15+b)= 44
=30+2b=44
2b=44-30
2b=14
so, b=7
area of rectangle= l*b
= 15*7
= 105 sq. cm
hope it helps..
=2(15+b)= 44
=30+2b=44
2b=44-30
2b=14
so, b=7
area of rectangle= l*b
= 15*7
= 105 sq. cm
hope it helps..
tnq soo much fr giving me right answer i have more doubts in maths will u clarify me plz
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