Question

the perimeter and of a tirangle whose sides 3 cm 4 cm and 5 cm reptively are

Answer 1

Answer:

Answer :

The perimeter of the triangle is 12 cm and the area of the triangle is 6 cm.

Given :

3 sides of the triangle is 3 cm , 4 cm and 5 cm respectively.

To find :

Perimeter and area of the triangle.

Solution :

Consider,

3 sides of the triangle is a cm, b cm and c cm respectively.

★Formula used :-

${\boxed{\sf{Perimeter\:of\: triangle=a+b+c}}}$

Then,

Perimeter of the triangle,

= (3+4+5) cm

= 12 cm

Therefore, perimeter of the triangle is 12 cm.

★Formula Used :-

${\boxed{\sf{Area\:of\: triangle=\sqrt{s(s-a)(s-b)(s-c)}}}}$

Where,

a = 3 cm

b = 4 cm

c = 5 cm

s = 12/2 = 6 cm

Area of the triangle ,

$= \sf{\sqrt{s(s-a)(s-b)(s-c)}}$

$= \sf{\sqrt{6(6-3)(6-4)(6-5)}}$

$= \sf{\sqrt{6\times\:3\times\:2\times\:1}}$

$= \sf{\sqrt{36}}$

${\boxed{\sf{Option (A)\:is\:correct.}}}$

Answer 2

Answer :

The perimeter of the triangle is 12 cm and the area of the triangle is 6 cm.

Given :

3 sides of the triangle is 3 cm , 4 cm and 5 cm respectively.

To find :

Perimeter and area of the triangle.

Solution :

Consider,

3 sides of the triangle is a cm, b cm and c cm respectively.

★Formula used :-

$</p><p>{\boxed{\sf{Perimeter\:of\: triangle=a+b+c}}}$

Then,

Perimeter of the triangle,

= (3+4+5) cm

= 12 cm

Therefore, perimeter of the triangle is 12 cm.

★Formula Used :-

$</p><p></p><p>{\boxed{\sf{Area\:of\: triangle=\sqrt{s(s-a)(s-b)(s-c)}}}}$

Where,

a = 3 cm

b = 4 cm

c = 5 cm

s = 12/2 = 6 cm

Area of the triangle ,

$</p><p>= \sf{\sqrt{s(s-a)(s-b)(s-c)}} \\ </p><p></p><p>= \sf{\sqrt{6(6-3)(6-4)(6-5)}} \\ </p><p></p><p>= \sf{\sqrt{6\times\:3\times\:2\times\:1}} \\ </p><p></p><p>= \sf{\sqrt{36}}</p><p> \\ </p><p>{\boxed{\sf{Option (A)\:is\:correct.}}}</p><p></p><p>$