the perimeter is 100 om free
8. The length of a rectangle is 20 cm more than its breadth if the perimeter is 100 cm,find
the dimension of the rectangle,
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Answer:
let b=X
l=20+X
p=2×(l+b)
100=2×(20+x+x)
100÷2=20+2x
50=20+2x
50-20=2x
30=2x
X=30÷2
x=15
b=15
l=20+15=35
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