The perimeter of 2 similar triangle are 40 cm and 50 cm respectively find the ratio of area of first triangle to that of second triangle .
Answers
Answered by
80
Hi
As we know that the ratio of perimeters of 2 similar triangles are equal to ratio of corresponding sides
I.e
perimeter of 1st / perimeter of second = side of 1st / side of 2nd
40 / 50 = side of 1st / side of 2nd
side of 1st / side of 2nd = 4 / 5
We know that " The ratio of two similar triangles are equal to the square of ratio of there corresponding sides
area of 1 st / area of 2nd = ( side of 1st / side of 2nd ) ^2 = (4 / 5 ) ^2
= 16 / 25
As we know that the ratio of perimeters of 2 similar triangles are equal to ratio of corresponding sides
I.e
perimeter of 1st / perimeter of second = side of 1st / side of 2nd
40 / 50 = side of 1st / side of 2nd
side of 1st / side of 2nd = 4 / 5
We know that " The ratio of two similar triangles are equal to the square of ratio of there corresponding sides
area of 1 st / area of 2nd = ( side of 1st / side of 2nd ) ^2 = (4 / 5 ) ^2
= 16 / 25
Answered by
61
Ratio of the perimeters of 2 similar triangles is always equal to the ratio of their corresponding sides,
so
perimeter of firstΔ / perimeter of second Δ = side of first Δ/side of secondΔ
= 40/50 = side of first Δ / side of second Δ
= side of first Δ / side of second Δ = 4/5
The ratio of the squares is equal to the ratios of similar triangles of their corresponding sides.
area of first Δ / area of second Δ = (side of first Δ/ side of the second Δ)² = (4/5)² = 16/25
so
perimeter of firstΔ / perimeter of second Δ = side of first Δ/side of secondΔ
= 40/50 = side of first Δ / side of second Δ
= side of first Δ / side of second Δ = 4/5
The ratio of the squares is equal to the ratios of similar triangles of their corresponding sides.
area of first Δ / area of second Δ = (side of first Δ/ side of the second Δ)² = (4/5)² = 16/25
Similar questions