the perimeter of a a square is 28cm find its length area and diagonal
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Answered by
2
Answer:
Perimeter of square = 4×side
28 = 4×side
side = 28/4 = 7
Area of square = side × side = 7×7 = 49
Area of square = 1/2×(diagonal)²
49 = 1/2×(diagonal)²
Diagonal ² = 49×2 = 98
Diagonal = ✓98
=9.8
Answered by
0
Answer:
length= 7 cm
area = 49 cm²
diagonal= 7 √2 cm
Step-by-step explanation:
perimeter of square= 4 X side
28=4Xside
28/4=side
side= 7cm
area = side X side
= 7X7 = 49 cm ²
diagonal
using pythogoras thereom
diagonal= √7²+7²
= √49+49
= 7√2
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