Math, asked by Mygapulanagaraju, 7 months ago

The perimeter of a badminton court is 150 meters and the length is twice the width, then the length of the court is _______ meters

Answers

Answered by pandaXop
66

Length = 50 m

Step-by-step explanation:

Given:

  • Perimeter of badminton court is 150 m.
  • Length of court is twice the breadth.

To Find:

  • What is the length of court?

Solution: Let the breadth of badminton court be x m. Therefore,

➯ Length = 2 times of x

➯ Length = 2x

As we know that

Perimeter of Rectangle = 2(Length + Breadth)

A/q

  • Perimeter is 150 m

\implies{\rm } 150 = 2(2x + x)

\implies{\rm } 150 = 2(3x)

\implies{\rm } 150 = 6x

\implies{\rm } 150/6 = x

\implies{\rm } 25 = x

So, the dimensions of court

➨ Breadth = x = 25 m

➨ Length = 2x = 2(25) = 50 m

__________________

★ Verification ★

=> 150 = 2(25 + 50)

=> 150 = 2(75)

=> 150 = 150

\large\boxed{\texttt{Verified}}


amitkumar44481: Nice :-)
Answered by Anonymous
74

Given :-

  • Perimeter of court = 150 m

  • Breadth of the court = x

  • Length of the court = 2x

To Find :-

  • Length of the court

Solution :-

Perimeter of the court = 2 ( L + B )

⇒ 150 = 2 ( 2x + x )

⇒ 150 = 2 × 3x

⇒ 150 = 6x

⇒ x = 150/6

⇒ x = 25

Lenght = 2x = 2 × 25 = 50 m

Lenght of the court is 50 m


amitkumar44481: Nice :-)
Anonymous: Nicee :D
Similar questions