Question

The perimeter of a badminton court is 40 m
The width of the badminton court is 6 m.
What is the ratio of the width to the length of
the badminton court?​

Answer 1

Step-by-step explanation:

Court dimensions

The badminton court is 13.4m long and 6.1m wide. For singles the court is marked 5.18m wide. The lines marking out the court are easily distinguishable and coloured white or yellow. The lines are 40mm wide.

Answer 2

Given:

• Perimeter of the badminton court = 40 m
• Width of the badminton court = 6 m

To Find:

• What is the ratio of the width to the length of the badminton court?

As, we know

Perimeter of a rectangle = 2(L + B)

Where,

L = length

B = breath

We will assume:

Length = x metres

Substituting the values, we get:

40 = 2 (x + 6)

After opening the brackets, we get:

40 = 2x + 12

After transposing like terms on the same side, we get:

-2x = 12 - 40

Solving further, we get:

-2x = -28

$\not\!\!\!{-}2x = \:\not\!\!\!{-}28$

2x = 28

After transposing 2 from LHS to RHS and changing it's sign, we get:

x = 28/2

After dividing 28 by 2, we get:

x = 14

Hence, the length of the badminton court is 14 m.

Ratio between the width and the length of the court:

6 : 14 = 6/14 = 3/7 = 3 : 7

Hence, the ratio of the width to the length of the badminton court is 3 : 7.