The perimeter of a certain sector of a circle of radius 9.5 cm is 41 cm. Find the area of the sector.
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2/3pi r^3=3pi r^2
r (2pi r^2)=9pi r^2
r=9pi r^2/2pi r^2
r=4.5
Diameter =2r
therefore, 2×4.5
= 9 cm
r (2pi r^2)=9pi r^2
r=9pi r^2/2pi r^2
r=4.5
Diameter =2r
therefore, 2×4.5
= 9 cm
shivavs:
can u explain me
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