Question

The perimeter of a floor of a room is 40m and it's height is 4m. Find the area of a the four walls of the room

Answer 1

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Answer 2

Given:- Perimeter of the rectangular floor:-40m

Height of the room:-4m

To find:- Area of the four walls or CSA of the room.

Solution:- We know that the CSA of a cuboid:- 2h(l+b)

or:- hx2(l+b)

Also, 2(l+b)= Perimeter of the rectangle. So,

CSA of Room:- hx40

:- 4x40

:- 160m^2

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